7x-2[x-8]=5[x+1]+7

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Solution for 7x-2[x-8]=5[x+1]+7 equation:


Simplifying
7x + -2[x + -8] = 5[x + 1] + 7

Reorder the terms:
7x + -2[-8 + x] = 5[x + 1] + 7
7x + [-8 * -2 + x * -2] = 5[x + 1] + 7
7x + [16 + -2x] = 5[x + 1] + 7

Reorder the terms:
16 + 7x + -2x = 5[x + 1] + 7

Combine like terms: 7x + -2x = 5x
16 + 5x = 5[x + 1] + 7

Reorder the terms:
16 + 5x = 5[1 + x] + 7
16 + 5x = [1 * 5 + x * 5] + 7
16 + 5x = [5 + 5x] + 7

Reorder the terms:
16 + 5x = 5 + 7 + 5x

Combine like terms: 5 + 7 = 12
16 + 5x = 12 + 5x

Add '-5x' to each side of the equation.
16 + 5x + -5x = 12 + 5x + -5x

Combine like terms: 5x + -5x = 0
16 + 0 = 12 + 5x + -5x
16 = 12 + 5x + -5x

Combine like terms: 5x + -5x = 0
16 = 12 + 0
16 = 12

Solving
16 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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